y'),那么有: - 对称点的y坐标不变,即y' = 2 - 对称点的x坐标满足:a = (1 + x') / 2,即x' = 2a - 1 因此,对称点A'的坐标为(2a - 1

y’),那么有: – 对称点的y坐标不变,即y’ = 2 – 对称点的x坐标满足:a = (1 + x’) / 2,即x’ = 2a – 1 因此,对称点A’的坐标为(2a – 1

2025年10月17日
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